Mathc initiation/Fichiers h : x 19c1b
Apparence
Installer et compiler ces fichiers dans votre répertoire de travail.
c1b.c |
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/* ---------------------------------- */
/* save as c1b.c */
/* ---------------------------------- */
#include "x_hfile.h"
#include "fb.h"
/* --------------------------------- */
int main(void)
{
double n;
double a;
double b;
double y0;
n = 10.0;
a = 1.0;
b = 2.0;
y0 = 3.0;
clrscrn();
printf(" Euler's method to approximate the solution\n"
" of the differential equation.\n\n"
" y' = %s\n\n",Ypeq);
p_Euler_s_Method(a,
b,
n,
y0,
Yp);
printf(" y_n = %.10f\n\n",
Euler_s_Method(a,
b,
n,
y0,
Yp)
);
printf(" The exact value is y = 7.38629\n\n");
stop();
clrscrn();
n = 100000;
printf(" Euler's method to approximate the solution\n"
" of the differential equation\n\n"
" y' = %s,\n\n with n = %.0f \n\n",Ypeq, n);
printf(" y_n = %.10f\n\n",
Euler_s_Method(a,
b,
n,
y0,
Yp)
);
printf(" The exact value is y = 7.38629\n\n");
stop();
return 0;
}
/* --------------------------------- */
/* --------------------------------- */
Calculons la solution numérique de l'équation
y' = 1 + y/x pour 1 < x < 2
avec comme condition initial y0 = 3. quand x = 1
Exemple de sortie écran 1 :
Euler's method to approximate the solution
of the differential equation.
y' = 1 + y/x
k | x_k | y_k
--------------------------
1 | 1.100 | +3.4000000000
2 | 1.200 | +3.8090909091
3 | 1.300 | +4.2265151515
4 | 1.400 | +4.6516317016
5 | 1.500 | +5.0838911089
6 | 1.600 | +5.5228171828
7 | 1.700 | +5.9679932567
8 | 1.800 | +6.4190516836
9 | 1.900 | +6.8756656660
10 | 2.000 | +7.3375428064
y_n = 7.3375428064
The exact value is y = 7.38629
Press return to continue.
Exemple de sortie écran : 2
Euler's method to approximate the solution
of the differential equation
y' = 1 + y/x,
with n = 100000
y_n = 7.3862893611
The exact value is y = 7.38629
Press return to continue.