Mathc initiation/Fichiers c : c29cb
Apparence
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c16b.c |
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/* --------------------------------- */
/* save as c16b.c */
/* --------------------------------- */
#include "x_hfile.h"
#include "fb.h"
/* --------------------------------- */
int main(void)
{
double h = .001;
pt3d p = i_pt3d(1,0,1);
v3d u = grad_fxyz(f,h,p);
clrscrn();
printf(" f : x,y,z -> %s\n\n\n",feq);
printf(" p(%+.3f,%+.3f,%+.3f)\n\n",p.x,p.y,p.z);
printf(" Find equations for the tangent plane\n");
printf(" and the normal line to the graph of\n");
printf(" the equation at the point P.\n\n\n");
printf(" The equations for the tangent plane is :\n\n");
printf(" %+.3f(x %+.3f)) %+.3f(y %+.3f) %+.3f(z %+.3f) = 0\n\n\n",
fxyz_x(f,h,p), -p.x,
fxyz_y(f,h,p), -p.y,
fxyz_z(f,h,p), -p.z);
printf(" grad(p)]p = %+.3fi %+.3fj %+.3fk \n\n",u.i,u.j,u.k);
printf(" p(%+.3f,%+.3f,%+.3f)\n\n",p.x,p.y,p.z);
stop();
clrscrn();
printf(" The normal line is parallel to,\n\n");
printf(" grad(p) = %+.3fi %+.3fj %+.3fk \n\n\n",u.i,u.j,u.k);
printf(" and passes throught p(%+.3f,%+.3f,%+.3f)\n\n",p.x,p.y,p.z);
printf(" x=%+6.3f %+6.3f t\n y=%+6.3f %+6.3f t\n z=%+6.3f %+6.3f t\n\n\n\n",
p.x, fxyz_x(f,h,p),
p.y, fxyz_y(f,h,p),
p.z, fxyz_z(f,h,p));
stop();
return 0;
}
/* ---------------------------------
An equation for the tangent plane to the graph
of z = f(x,y,z) at the point (x0,y0,z0) is
f_x(x0,y0,z0)(x-x0)+f_y(x0,y0,z0)(y-y0)+f_z(x0,y0,z0)(z-z0) = 0
A normal vector of z = f(x,y,z) at
the point (x0,y0,z0) is
grad(p)]p0 = f_x(x0,y0,z0)i+f_y(x0,y0,z0)j+f_z(x0,y0,z0)k
------------------------------------ */
/* --------------------------------- */
/* --------------------------------- */
L'équation du plan tangent au point P0 est donnée par :
f_x(x0,y0,z0)(x-x0)+f_y(x0,y0,z0)(y-y0)+f_z(x0,y0,z0)(z-z0) = 0 Le vecteur normal au point P0 est donné par le gradient : grad(p)]p0 = f_x(x0,y0,z0)i+f_y(x0,y0,z0)j+f_z(x0,y0,z0)k Les équations paramétriques de la droite normale au point P0 est donné par :
x= x0 + f_x(x0,y0,z0) t y= y0 + f_y(x0,y0,z0) t z= z0 + f_z(x0,y0,z0) t
Exemple de sortie écran :
f : x,y,z -> 2*exp(-x) * cos(y) - z
p(+1.000,+0.000,+1.000)
Find equations for the tangent plane
and the normal line to the graph of
the equation at the point P.
The equations for the tangent plane is :
-0.736(x -1.000)) +0.000(y -0.000) -1.000(z -1.000) = 0
grad(p)]p = -0.736i +0.000j -1.000k
p(+1.000,+0.000,+1.000)
Press return to continue.
Exemple de sortie écran :
The normal line is parallel to,
grad(p) = -0.736i +0.000j -1.000k
and passes throught p(+1.000,+0.000,+1.000)
x=+1.000 -0.736 t
y=+0.000 +0.000 t
z=+1.000 -1.000 t
Press return to continue.